What is expand ((-2+x)^2)/4 ?

The solution to expand ((-2+x)^2)/4 is (x^2)/4-x+1

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expand ((-2+x)^2)/4

expand

\frac{( - 2 + x ) ^{2}}{4}

\frac{x ^{2}}{4} - x + 1

Solution steps

\frac{( - 2 + x ) ^{2}}{4}

(- 2 + x)^{2} = 4 - 4 x + x^{2}

= \frac{4 - 4 x + x ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 - 4 x + x ^{2}}{4} = \frac{4}{4} - \frac{4 x}{4} + \frac{x ^{2}}{4}

= \frac{4}{4} - \frac{4 x}{4} + \frac{x ^{2}}{4}

Apply rule

\frac{a}{a} = 1

\frac{4}{4} = 1

= 1 - \frac{4 x}{4} + \frac{x ^{2}}{4}

Divide the numbers:

\frac{4}{4} = 1

= 1 - x + \frac{x ^{2}}{4}

Rewrite in standard form

= \frac{x ^{2}}{4} - x + 1

\frac{z ^{2} - z + 0.64}{( z - 1 ) ( z - 0.36 )} - 1

s (t - \frac{π}{3}) cos (3 t)

- \frac{6}{( 1 + x ) ^{4}}

\frac{( x + h ) ^{2} - 3 - x ^{2} - 3}{h}

\frac{4 x ^{2} - x + 6}{( x ^{2} + 2 ) ( x - 1 )}

What is expand ((-2+x)^2)/4 ?
The solution to expand ((-2+x)^2)/4 is (x^2)/4-x+1