What is expand (6y-24xy^5)dx+(9x-56x^2y^4)y^' ?

The solution to expand (6y-24xy^5)dx+(9x-56x^2y^4)y^' is 6ydx-24y^5xdx+9xy^'-56x^2y^{4+'}

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expand (6y-24xy^5)dx+(9x-56x^2y^4)y^'

expand

(6 y - 24 x y^{5}) d x + (9 x - 56 x^{2} y^{4}) y^{^{'}}

6 y d x - 24 y^{5} x d x + 9 x y^{'} - 56 x^{2} y^{4 +'}

Solution steps

(6 y - 24 x y^{5}) d x + (9 x - 56 x^{2} y^{4}) y^{^{'}}

= (6 y - 24 y^{5} x) d x + y^{^{^{'}}} (9 x - 56 y^{4} x^{2})

Expand

d x (6 y - 24 x y^{5}) : 6 y d x - 24 y^{5} x d x

= 6 y d x - 24 y^{5} x d x + (9 x - 56 x^{2} y^{4}) y^{^{'}}

Expand

y^{^{'}} (9 x - 56 x^{2} y^{4}) : 9 x y^{^{'}} - 56 x^{2} y^{4 +^{'}}

= 6 y d x - 24 y^{5} x d x + 9 x y^{^{'}} - 56 x^{2} y^{4 +^{'}}

- \frac{( 1 + y ) ( - 1 - 2 x - 2 x y )}{3 + x + 6 y + 3 y ^{2}}

e^{x} \cdot (sin (x + y) + cos (x + y) + 1)

\frac{d}{d t} ((x) (t^{2} + 6))

\frac{\frac{d}{d x} ( 1 + x ( lo g _{10} ( x ) + 1 ) )}{x}

\frac{x ( x + 1 ) ( x + 55 )}{( x - 5 ) ( x + 5 ) ( 5 x + 3 )}

What is expand (6y-24xy^5)dx+(9x-56x^2y^4)y^' ?
The solution to expand (6y-24xy^5)dx+(9x-56x^2y^4)y^' is 6ydx-24y^5xdx+9xy^'-56x^2y^{4+'}