What is expand ,(2+2/7)(1+1/6)(2+2/3)*1/8 ?

The solution to expand ,(2+2/7)(1+1/6)(2+2/3)*1/8 is 8/9

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expand ,(2+2/7)(1+1/6)(2+2/3)*1/8

expand

(2 + \frac{2}{7}) (1 + \frac{1}{6}) (2 + \frac{2}{3}) \cdot \frac{1}{8}

\frac{8}{9}

Solution steps

(2 + \frac{2}{7}) (1 + \frac{1}{6}) (2 + \frac{2}{3}) \frac{1}{8}

= \frac{1}{8} (2 + \frac{2}{7}) (1 + \frac{1}{6}) (2 + \frac{2}{3})

Apply FOIL method

(2 + \frac{2}{7}) (1 + \frac{1}{6}) : \frac{8}{3}

= \frac{1}{8} \cdot \frac{8}{3} (2 + \frac{2}{3})

Apply the distributive law:

a (b + c) = ab + a c

\frac{1}{8} \cdot \frac{8}{3} (2 + \frac{2}{3}) = \frac{1}{8} \cdot \frac{8}{3} \cdot 2 + \frac{1}{8} \cdot \frac{8}{3} \cdot \frac{2}{3}

= \frac{1}{8} \cdot \frac{8}{3} \cdot 2 + \frac{1}{8} \cdot \frac{8}{3} \cdot \frac{2}{3}

\frac{1}{8} \cdot \frac{8}{3} \cdot 2 + \frac{1}{8} \cdot \frac{8}{3} \cdot \frac{2}{3} = \frac{8}{9}

= \frac{8}{9}

cos (x + y) (1 + y^{'} (x))

(2 z - 6 w (z) = 0,) (- z + 2 w (z) = - 8)

\frac{( 49 s ^{2} + 2 ( 7 s + 1 ) )}{s ^{3}}

\frac{5}{( s + 3 ) ^{2} ( s + 1 )}

f (3 x^{2} - 36 x) d x

What is expand ,(2+2/7)(1+1/6)(2+2/3)*1/8 ?
The solution to expand ,(2+2/7)(1+1/6)(2+2/3)*1/8 is 8/9