What is expand 1/((x^2-1)(x^2+x+1)) ?

The solution to expand 1/((x^2-1)(x^2+x+1)) is 1/(x^4+x^3-x-1)

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expand 1/((x^2-1)(x^2+x+1))

expand

\frac{1}{( x ^{2} - 1 ) ( x ^{2} + x + 1 )}

\frac{1}{x ^{4} + x ^{3} - x - 1}

Solution steps

\frac{1}{( x ^{2} - 1 ) ( x ^{2} + x + 1 )}

Expand

(x^{2} - 1) (x^{2} + x + 1) : x^{4} + x^{3} - x - 1

= \frac{1}{x ^{4} + x ^{3} - x - 1}

x H (x - 1) + (4 - 2 x) H (x - 2) - (3 - x) H (x - 3)

(3 cos (x) - 7 sin (x)) d x

\frac{( x ^{2} + 4 x ) ^{2}}{e ^{2 x}}

\frac{1}{( x + 5 ) ( x - 5 )}

\frac{d}{d θ} ((r (θ)) (1 - cos (θ)))

What is expand 1/((x^2-1)(x^2+x+1)) ?
The solution to expand 1/((x^2-1)(x^2+x+1)) is 1/(x^4+x^3-x-1)