What is the d/(dθ)(({r}(θ))(1-cos(θ))) ?

The d/(dθ)(({r}(θ))(1-cos(θ))) is d/(dθ)({r}(θ))(1-cos(θ))+sin(θ){r}(θ)

What is the first d/(dθ)(({r}(θ))(1-cos(θ))) ?

The first d/(dθ)(({r}(θ))(1-cos(θ))) is d/(dθ)({r}(θ))(1-cos(θ))+sin(θ){r}(θ)

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\frac{d}{d θ} ((r (θ)) (1 - cos (θ)))

\frac{d}{d θ} (r (θ)) (1 - cos (θ)) + sin (θ) r (θ)

Solution steps

\frac{d}{d θ} ((r (θ)) (1 - cos (θ)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = r (θ), g = 1 - cos (θ)

= \frac{d}{d θ} (r (θ)) (1 - cos (θ)) + \frac{d}{d θ} (1 - cos (θ)) r (θ)

\frac{d}{d θ} (1 - cos (θ)) = sin (θ)

= \frac{d}{d θ} (r (θ)) (1 - cos (θ)) + sin (θ) r (θ)

- \frac{( 4 x + 1 ) ( x - 2 )}{2}

\frac{50}{( x + y ) ^{3}}

\frac{252 x}{( 4 + x ) ^{5}}

\frac{1 0 ^{43}}{1 0 ^{17}}

\frac{x ^{3} - 3}{( x - 1 ) ^{3}}

What is the d/(dθ)(({r}(θ))(1-cos(θ))) ?
The d/(dθ)(({r}(θ))(1-cos(θ))) is d/(dθ)({r}(θ))(1-cos(θ))+sin(θ){r}(θ)
What is the first d/(dθ)(({r}(θ))(1-cos(θ))) ?
The first d/(dθ)(({r}(θ))(1-cos(θ))) is d/(dθ)({r}(θ))(1-cos(θ))+sin(θ){r}(θ)