What is expand ((8+x)(x^2+x-2))/2 ?

The solution to expand ((8+x)(x^2+x-2))/2 is (x^3)/2+(9x^2)/2+3x-8

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expand ((8+x)(x^2+x-2))/2

expand

\frac{( 8 + x ) ( x ^{2} + x - 2 )}{2}

\frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + 3 x - 8

Solution steps

\frac{( 8 + x ) ( x ^{2} + x - 2 )}{2}

Expand

(8 + x) (x^{2} + x - 2) : x^{3} + 9 x^{2} + 6 x - 16

= \frac{x ^{3} + 9 x ^{2} + 6 x - 16}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 9 x ^{2} + 6 x - 16}{2} = \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{6 x}{2} - \frac{16}{2}

= \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{6 x}{2} - \frac{16}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + 3 x - \frac{16}{2}

Divide the numbers:

\frac{16}{2} = 8

= \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + 3 x - 8

\frac{x + 1 - x ^{2}}{2 x - ( x + 1 ) ( x - 1 )}

\frac{( 1 )}{( x ( x + 1 ) )}

1 - e^{10 k - 10 (a_{0} + 0.00512)}

e^{2 x} (x - 1) + (x - 1) e^{x}

20 (4 x^{3} - 3 x)^{19} (12 x^{2} - 3)

What is expand ((8+x)(x^2+x-2))/2 ?
The solution to expand ((8+x)(x^2+x-2))/2 is (x^3)/2+(9x^2)/2+3x-8