What is expand 20(4x^3-3x)^{19}(12x^2-3) ?

The solution to expand 20(4x^3-3x)^{19}(12x^2-3) is 20*12x^2(4x^3-3x)^{19}-20*3(4x^3-3x)^{19}

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expand 20(4x^3-3x)^{19}(12x^2-3)

expand

20 (4 x^{3} - 3 x)^{19} (12 x^{2} - 3)

20 \cdot 12 x^{2} (4 x^{3} - 3 x)^{19} - 20 \cdot 3 (4 x^{3} - 3 x)^{19}

Solution steps

20 (4 x^{3} - 3 x)^{19} (12 x^{2} - 3)

Apply the distributive law:

a (b - c) = ab - a c

a = 20 (4 x^{3} - 3 x)^{19}, b = 12 x^{2}, c = 3

= 20 (4 x^{3} - 3 x)^{19} \cdot 12 x^{2} - 20 (4 x^{3} - 3 x)^{19} \cdot 3

= 20 \cdot 12 x^{2} (4 x^{3} - 3 x)^{19} - 20 \cdot 3 (4 x^{3} - 3 x)^{19}

e^{2 t} (7 sin (t) - cosh (3 t))

n gu l a r (- 2, - \frac{π}{3})

(k + 1)! \cdot (k + 2)

\frac{v ^{3}}{( v ^{2} + 1 ) ( 2 v ^{2} + 1 )}

\frac{( x ^{2} - 3 x + 10 )}{( x - 2 ) ( x ^{2} + 4 )}

What is expand 20(4x^3-3x)^{19}(12x^2-3) ?
The solution to expand 20(4x^3-3x)^{19}(12x^2-3) is 20*12x^2(4x^3-3x)^{19}-20*3(4x^3-3x)^{19}