What is expand (-x^2+3-e^{4x-3})^2 ?

The solution to expand (-x^2+3-e^{4x-3})^2 is x^4-6x^2+2e^{4x-3}x^2-6e^{4x-3}+e^{8x-6}+9

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expand (-x^2+3-e^{4x-3})^2

expand

(- x^{2} + 3 - e^{4 x - 3})^{2}

x^{4} - 6 x^{2} + 2 e^{4 x - 3} x^{2} - 6 e^{4 x - 3} + e^{8 x - 6} + 9

Solution steps

(- x^{2} + 3 - e^{4 x - 3})^{2}

(- x^{2} + 3 - e^{4 x - 3})^{2} = (- x^{2} + 3 - e^{4 x - 3}) (- x^{2} + 3 - e^{4 x - 3})

= (- x^{2} - e^{4 x - 3} + 3) (- x^{2} - e^{4 x - 3} + 3)

Expand

(- x^{2} + 3 - e^{4 x - 3}) (- x^{2} + 3 - e^{4 x - 3}) : x^{4} - 6 x^{2} + 2 e^{4 x - 3} x^{2} - 6 e^{4 x - 3} + e^{8 x - 6} + 9

= x^{4} - 6 x^{2} + 2 e^{4 x - 3} x^{2} - 6 e^{4 x - 3} + e^{8 x - 6} + 9

(csc (x) cot (x) - 2 x) d x

\frac{( 1 + ln ( x ) ) ^{2}}{x}

\frac{d}{d x} ((x + 6) (2 x^{2} + 4 x)) + 3

\frac{5}{x + 1} + \frac{( 3 x - 1 )}{x ^{2} + x + 1}

(- e^{2 t} sin (t) + e^{2 t} cos (t))^{2}

What is expand (-x^2+3-e^{4x-3})^2 ?
The solution to expand (-x^2+3-e^{4x-3})^2 is x^4-6x^2+2e^{4x-3}x^2-6e^{4x-3}+e^{8x-6}+9