What is expand derivative of (x+6(2x^2+4x))+3 ?

The solution to expand derivative of (x+6(2x^2+4x))+3 is derivative of 2x^3+16x^2+24x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand derivative of (x+6(2x^2+4x))+3

expand

\frac{d}{d x} ((x + 6) (2 x^{2} + 4 x)) + 3

\frac{d}{d x} (2 x^{3} + 16 x^{2} + 24 x) + 3

Solution steps

\frac{d}{d x} ((x + 6) (2 x^{2} + 4 x)) + 3

Expand

(x + 6) (2 x^{2} + 4 x) : 2 x^{3} + 16 x^{2} + 24 x

= \frac{d}{d x} (2 x^{3} + 16 x^{2} + 24 x) + 3

\frac{5}{x + 1} + \frac{( 3 x - 1 )}{x ^{2} + x + 1}

(- e^{2 t} sin (t) + e^{2 t} cos (t))^{2}

\frac{3 ( x ^{2} - 9 x + 20 )}{2}

(x^{2} - 5 e x + 3) (x^{3} + 2 x + 1)

1 + (\frac{( x ^{4} + 9 )}{( 18 x )})^{2}

What is expand derivative of (x+6(2x^2+4x))+3 ?
The solution to expand derivative of (x+6(2x^2+4x))+3 is derivative of 2x^3+16x^2+24x+3