What is expand 1+(((x^4+9))/((18x)))^2 ?

The solution to expand 1+(((x^4+9))/((18x)))^2 is 1+(x^6)/(324)+(x^2)/(18)+1/(4x^2)

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expand 1+(((x^4+9))/((18x)))^2

expand

1 + (\frac{( x ^{4} + 9 )}{( 18 x )})^{2}

1 + \frac{x ^{6}}{324} + \frac{x ^{2}}{18} + \frac{1}{4 x ^{2}}

Solution steps

1 + (\frac{x ^{4} + 9}{18 x})^{2}

(\frac{x ^{4} + 9}{18 x})^{2} = \frac{x ^{8} + 18 x ^{4} + 81}{1 8 ^{2} x ^{2}}

= 1 + \frac{x ^{8} + 18 x ^{4} + 81}{1 8 ^{2} x ^{2}}

1 8^{2} = 324

= 1 + \frac{x ^{8} + 18 x ^{4} + 81}{324 x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{8} + 18 x ^{4} + 81}{324 x ^{2}} = \frac{x ^{8}}{324 x ^{2}} + \frac{18 x ^{4}}{324 x ^{2}} + \frac{81}{324 x ^{2}}

= 1 + \frac{x ^{8}}{324 x ^{2}} + \frac{18 x ^{4}}{324 x ^{2}} + \frac{81}{324 x ^{2}}

Cancel

\frac{x ^{8}}{324 x ^{2}} : \frac{x ^{6}}{324}

= 1 + \frac{x ^{6}}{324} + \frac{18 x ^{4}}{324 x ^{2}} + \frac{81}{324 x ^{2}}

Cancel

\frac{18 x ^{4}}{324 x ^{2}} : \frac{x ^{2}}{18}

= 1 + \frac{x ^{6}}{324} + \frac{x ^{2}}{18} + \frac{81}{324 x ^{2}}

Cancel

\frac{81}{324 x ^{2}} : \frac{1}{4 x ^{2}}

= 1 + \frac{x ^{6}}{324} + \frac{x ^{2}}{18} + \frac{1}{4 x ^{2}}

(bi + c j + d k)^{2}

(1 + e^{x}) d x

\frac{- 6 x ^{2} - 43 x + 103}{( x + 5 ) ( x + 2 ) ( x + 13 )}

(x^{2} - 2 x y + y^{2} = 3) (- 1)

\frac{60 ( s + 6 )}{s ^{3} + 9 s + 168}

What is expand 1+(((x^4+9))/((18x)))^2 ?
The solution to expand 1+(((x^4+9))/((18x)))^2 is 1+(x^6)/(324)+(x^2)/(18)+1/(4x^2)