What is (\partial)/(\partial u)((x)(v-u)) ?

The answer to (\partial)/(\partial u)((x)(v-u)) is -x

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(\partial)/(\partial u)((x)(v-u))

\frac{\partial}{\partial u} ((x) (v - u))

- x

Solution steps

\frac{\partial}{\partial u} ((x) (v - u))

Treat

x, v

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial u} (v - u)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{\partial}{\partial u} (v) - \frac{\partial}{\partial u} (u))

\frac{\partial}{\partial u} (v) = 0

\frac{\partial}{\partial u} (u) = 1

= x (0 - 1)

Simplify

= - x

\frac{( - x + 2 ) ^{3}}{12}

x (x ln (x) - x)

\frac{\partial}{\partial s} ((f (s, t)) (s^{2} - t^{2}))

\frac{( x + 4 )}{( ( 3 \cdot x + 1 ) \cdot ( x ^{3} + 3 \cdot x ^{2} + 7 \cdot x ) )}

\frac{( x + 3 ) ^{2}}{x}

What is (\partial)/(\partial u)((x)(v-u)) ?
The answer to (\partial)/(\partial u)((x)(v-u)) is -x