What is expand (((a*(1+g)^n)*(1-0.6a))-20)/(20) ?

The solution to expand (((a*(1+g)^n)*(1-0.6a))-20)/(20) is (a(1+g)^n)/(20)-(0.6a^2(1+g)^n)/(20)-1

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expand (((a(1+g)^n)(1-0.6a))-20)/(20)

expand

\frac{( ( a \cdot ( 1 + g ) ^{n} ) \cdot ( 1 - 0.6 a ) ) - 20}{20}

\frac{a ( 1 + g ) ^{n}}{20} - \frac{0.6 a ^{2} ( 1 + g ) ^{n}}{20} - 1

Solution steps

\frac{( ( a ( 1 + g ) ^{n} ) ( 1 - 0.6 a ) ) - 20}{20}

Remove parentheses:

(a) = a

= \frac{a ( 1 + g ) ^{n} ( 1 - 0.6 a ) - 20}{20}

Expand

a (1 + g)^{n} (1 - 0.6 a) - 20 : a (1 + g)^{n} - 0.6 a^{2} (1 + g)^{n} - 20

= \frac{a ( g + 1 ) ^{n} - 0.6 a ^{2} ( g + 1 ) ^{n} - 20}{20}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a ( 1 + g ) ^{n} - 0.6 a ^{2} ( 1 + g ) ^{n} - 20}{20} = \frac{a ( 1 + g ) ^{n}}{20} - \frac{0.6 a ^{2} ( 1 + g ) ^{n}}{20} - \frac{20}{20}

= \frac{a ( g + 1 ) ^{n}}{20} - \frac{0.6 a ^{2} ( g + 1 ) ^{n}}{20} - \frac{20}{20}

Apply rule

\frac{a}{a} = 1

\frac{20}{20} = 1

= \frac{a ( g + 1 ) ^{n}}{20} - \frac{0.6 a ^{2} ( g + 1 ) ^{n}}{20} - 1

\frac{e ^{- 4 s} ( \frac{1}{s ^{2}} + \frac{3}{s} ) - 5}{s ^{2} + 5 s + 8}

- \frac{2 x ( - 2 x + 6 ) ^{3}}{81}

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What is expand (((a*(1+g)^n)*(1-0.6a))-20)/(20) ?
The solution to expand (((a*(1+g)^n)*(1-0.6a))-20)/(20) is (a(1+g)^n)/(20)-(0.6a^2(1+g)^n)/(20)-1