What is expand ((3x+1)(x+2))/(x-1) ?

The solution to expand ((3x+1)(x+2))/(x-1) is (3x^2+7x+2)/(x-1)

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expand ((3x+1)(x+2))/(x-1)

expand

\frac{( 3 x + 1 ) ( x + 2 )}{x - 1}

\frac{3 x ^{2} + 7 x + 2}{x - 1}

Solution steps

\frac{( 3 x + 1 ) ( x + 2 )}{x - 1}

Expand

(3 x + 1) (x + 2) : 3 x^{2} + 7 x + 2

= \frac{3 x ^{2} + 7 x + 2}{x - 1}

\frac{1}{( ( a + h ) ^{2} + 1 )}

(1 - \frac{δ}{R})^{2}

\frac{4 x}{( x ^{2} + 1 ) ( x ^{2} + 2 x + 3 )}

(x - 6) x + 6 + 7

(e^{i x} + e^{- i x})^{2}

What is expand ((3x+1)(x+2))/(x-1) ?
The solution to expand ((3x+1)(x+2))/(x-1) is (3x^2+7x+2)/(x-1)