What is expand (e^{ix}+e^{-ix})^2 ?

The solution to expand (e^{ix}+e^{-ix})^2 is 4cos^2(x)

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expand (e^{ix}+e^{-ix})^2

expand

(e^{i x} + e^{- i x})^{2}

4 cos^{2} (x)

Solution steps

(e^{i x} + e^{- i x})^{2}

e^{i x} = cos (x) + i sin (x)

e^{- i x} = cos (x) - i sin (x)

= (cos (x) + i sin (x) + cos (x) - i sin (x))^{2}

Simplify

cos (x) + sin (x) i + cos (x) - i sin (x) : 2 cos (x)

= (2 cos (x))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 2^{2} cos^{2} (x)

2^{2} = 4

= 4 cos^{2} (x)

A (3, 0, - 1) B (0, - 2, 0)

\frac{3.0685}{x ( x + 0.2933 )}

(a + c = 40, 0) (25 a + 15 c = 7550)

\frac{2 n}{n + 4} + \frac{7}{n - 1}

\frac{( e ^{\frac{x}{a}} - e ^{- \frac{x}{a}} ) ^{2}}{4}

What is expand (e^{ix}+e^{-ix})^2 ?
The solution to expand (e^{ix}+e^{-ix})^2 is 4cos^2(x)