What is expand (2n)/(n+4)+7/(n-1) ?

The solution to expand (2n)/(n+4)+7/(n-1) is (2n^2+5n+28)/(n^2+3n-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2n)/(n+4)+7/(n-1)

expand

\frac{2 n}{n + 4} + \frac{7}{n - 1}

\frac{2 n ^{2} + 5 n + 28}{n ^{2} + 3 n - 4}

Solution steps

\frac{2 n}{n + 4} + \frac{7}{n - 1}

Least Common Multiplier of

n + 4, n - 1 : (n + 4) (n - 1)

Adjust Fractions based on the LCM

= \frac{2 n ( n - 1 )}{( n + 4 ) ( n - 1 )} + \frac{7 ( n + 4 )}{( n - 1 ) ( n + 4 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 n ( n - 1 ) + 7 ( n + 4 )}{( n + 4 ) ( n - 1 )}

Expand

(n + 4) (n - 1) : n^{2} + 3 n - 4

= \frac{2 n ( n - 1 ) + 7 ( n + 4 )}{n ^{2} + 3 n - 4}

Expand

2 n (n - 1) + 7 (n + 4) : 2 n^{2} + 5 n + 28

= \frac{2 n ^{2} + 5 n + 28}{n ^{2} + 3 n - 4}

\frac{( e ^{\frac{x}{a}} - e ^{- \frac{x}{a}} ) ^{2}}{4}

\frac{10 s + 4}{s ( s + 1 ) ( s ^{2} + 4 s + 5 )}

e^{2} (y + 2 z) d z

(3 x - 1) (2 x e^{3} + 4 x^{2} - 5)

\frac{( 1 + sin ( x ) ) ^{2}}{2}

What is expand (2n)/(n+4)+7/(n-1) ?
The solution to expand (2n)/(n+4)+7/(n-1) is (2n^2+5n+28)/(n^2+3n-4)