What is expand (e^{2x}-1)(e^{2x}+1) ?

The solution to expand (e^{2x}-1)(e^{2x}+1) is e^{4x}-1

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expand (e^{2x}-1)(e^{2x}+1)

expand

(e^{2 x} - 1) (e^{2 x} + 1)

e^{4 x} - 1

Solution steps

(e^{2 x} - 1) (e^{2 x} + 1)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{2 x}, b = 1

= (e^{2 x})^{2} - 1^{2}

Simplify

(e^{2 x})^{2} - 1^{2} : e^{4 x} - 1

= e^{4 x} - 1

\frac{1}{s ^{2} ( s ^{2} + 2 s + 2 ) - s}

\frac{- 3 s - 5}{2 ( s + 1 ) ( s + 4 ) ( s + 3 )}

\frac{3}{x + 5} + \frac{7}{x - 2}

18 ((x - 1)^{3} (x - 3)^{11})

(6 x y^{3} + cos (y)) d x + (3 k x^{2} y^{2} - 3 y^{2}) d y

What is expand (e^{2x}-1)(e^{2x}+1) ?
The solution to expand (e^{2x}-1)(e^{2x}+1) is e^{4x}-1