What is expand 3/(x+5)+7/(x-2) ?

The solution to expand 3/(x+5)+7/(x-2) is (10x+29)/(x^2+3x-10)

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expand 3/(x+5)+7/(x-2)

expand

\frac{3}{x + 5} + \frac{7}{x - 2}

\frac{10 x + 29}{x ^{2} + 3 x - 10}

Solution steps

\frac{3}{x + 5} + \frac{7}{x - 2}

Least Common Multiplier of

x + 5, x - 2 : (x + 5) (x - 2)

Adjust Fractions based on the LCM

= \frac{3 ( x - 2 )}{( x + 5 ) ( x - 2 )} + \frac{7 ( x + 5 )}{( x - 2 ) ( x + 5 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 ( x - 2 ) + 7 ( x + 5 )}{( x + 5 ) ( x - 2 )}

Expand

(x + 5) (x - 2) : x^{2} + 3 x - 10

= \frac{3 ( x - 2 ) + 7 ( x + 5 )}{x ^{2} + 3 x - 10}

Expand

3 (x - 2) + 7 (x + 5) : 10 x + 29

= \frac{10 x + 29}{x ^{2} + 3 x - 10}

18 ((x - 1)^{3} (x - 3)^{11})

(6 x y^{3} + cos (y)) d x + (3 k x^{2} y^{2} - 3 y^{2}) d y

f (15 x^{4} - 33 x^{2} + 4) d x

\frac{s + 6}{( s - 1 ) ( s - 2 ) ^{2}}

\frac{( 2 x + 1 ) ( x - 9 )}{x + 7}

What is expand 3/(x+5)+7/(x-2) ?
The solution to expand 3/(x+5)+7/(x-2) is (10x+29)/(x^2+3x-10)