What is expand ((3x+4)^3)/3 ?

The solution to expand ((3x+4)^3)/3 is 9x^3+36x^2+48x+64/3

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expand ((3x+4)^3)/3

expand

\frac{( 3 x + 4 ) ^{3}}{3}

9 x^{3} + 36 x^{2} + 48 x + \frac{64}{3}

Solution steps

\frac{( 3 x + 4 ) ^{3}}{3}

(3 x + 4)^{3} = 27 x^{3} + 108 x^{2} + 144 x + 64

= \frac{27 x ^{3} + 108 x ^{2} + 144 x + 64}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} + 108 x ^{2} + 144 x + 64}{3} = \frac{27 x ^{3}}{3} + \frac{108 x ^{2}}{3} + \frac{144 x}{3} + \frac{64}{3}

= \frac{27 x ^{3}}{3} + \frac{108 x ^{2}}{3} + \frac{144 x}{3} + \frac{64}{3}

Divide the numbers:

\frac{27}{3} = 9

= 9 x^{3} + \frac{108 x ^{2}}{3} + \frac{144 x}{3} + \frac{64}{3}

Divide the numbers:

\frac{108}{3} = 36

= 9 x^{3} + 36 x^{2} + \frac{144 x}{3} + \frac{64}{3}

Divide the numbers:

\frac{144}{3} = 48

= 9 x^{3} + 36 x^{2} + 48 x + \frac{64}{3}

(1 + e^{x}) y^{'} (x)

ln (x) (x - ln (x)) + 1

(1 - e^{- b t}) u (t)

\frac{s ^{2}}{2 ( s - 2 )}

(1 - t) (1) + (t) (1)

What is expand ((3x+4)^3)/3 ?
The solution to expand ((3x+4)^3)/3 is 9x^3+36x^2+48x+64/3