What is expand ((x-1)(x+1))/(3-2x) ?

The solution to expand ((x-1)(x+1))/(3-2x) is (x^2-1)/(3-2x)

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expand ((x-1)(x+1))/(3-2x)

expand

\frac{( x - 1 ) ( x + 1 )}{3 - 2 x}

\frac{x ^{2} - 1}{3 - 2 x}

Solution steps

\frac{( x - 1 ) ( x + 1 )}{3 - 2 x}

Expand

(x - 1) (x + 1) : x^{2} - 1

= \frac{x ^{2} - 1}{3 - 2 x}

\frac{4 x ^{3}}{( x ^{4} + 1 ) ^{2}}

\frac{2}{5 ( 2 x + 3 )}

\frac{x - 3}{( 2 x + 1 ) ( 3 x - 2 )}

y^{'} (x) - \frac{( x ^{2} + 1 ) ( y ^{2} + 1 )}{x ( y - 1 )}

\frac{( y - x ) ( y + x ) ( x y ^{'} ( x ) - y )}{x ^{2} y ^{2}}

What is expand ((x-1)(x+1))/(3-2x) ?
The solution to expand ((x-1)(x+1))/(3-2x) is (x^2-1)/(3-2x)