What is expand 901^'-(0-3*180+240+150+2401^') ?

The solution to expand 901^'-(0-3*180+240+150+2401^') is 90*1^'-0+3*180-240-150-240*1^'

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expand 901^'-(0-3*180+240+150+2401^')

expand

9 0^{\circ} 1^{^{'}} - (0^{\circ} - 3 \cdot 180 + 240 + 150 + 24 0^{\circ} 1^{^{'}})

9 0^{\circ} \cdot 1^{'} - 0^{\circ} + 3 \cdot 180 - 240 - 150 - 24 0^{\circ} \cdot 1^{'}

Solution steps

9 0^{\circ} \cdot 1^{^{'}} - (0^{\circ} - 3 \cdot 180 + 240 + 150 + 24 0^{\circ} \cdot 1^{^{'}})

- (0^{\circ} - 3 \cdot 180 + 240 + 150 + 24 0^{\circ} \cdot 1^{^{'}}) : - 0^{\circ} + 3 \cdot 180 - 240 - 150 - 24 0^{\circ} \cdot 1^{^{'}}

= 9 0^{\circ} \cdot 1^{^{'}} - 0^{\circ} + 3 \cdot 180 - 240 - 150 - 24 0^{\circ} \cdot 1^{^{'}}

(e^{x} - e^{- x})^{7}

\frac{( 3 - x ) ( 4 - x )}{12}

(e^{x} - e^{- x})^{5}

\frac{4 x}{( 3 x ^{2} - 1 ) ^{2}}

\frac{( 2 a ^{2} b ^{4} - a ^{4} b ) ^{3}}{8}

What is expand 901^'-(0-3*180+240+150+2401^') ?
The solution to expand 901^'-(0-3*180+240+150+2401^') is 90*1^'-0+3*180-240-150-240*1^'