What is expand ln(b^2+(x-a)^2) ?

The solution to expand ln(b^2+(x-a)^2) is ln(b^2+x^2-2ax+a^2)

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expand ln(b^2+(x-a)^2)

expand

ln (b^{2} + (x - a)^{2})

ln (b^{2} + x^{2} - 2 a x + a^{2})

Solution steps

ln (b^{2} + (x - a)^{2})

Expand

b^{2} + (x - a)^{2} : b^{2} + x^{2} - 2 x a + a^{2}

= ln (b^{2} + x^{2} - 2 a x + a^{2})

\frac{4 x ^{2} - 6 x}{3 ( x - 3 ) ( x ^{2} + 9 )}

\frac{1}{1 - cos ( 3 0 ^{\circ} )} - \frac{1}{1 + cos ( 3 0 ^{\circ} )}

(2 x - 3 y^{2}) d x + (- y^{3}) d y

\frac{1}{s ^{2} ( t s + 1 )}

\frac{( x + 1 ) d x}{( x ^{2} ( x - 1 ) )}

What is expand ln(b^2+(x-a)^2) ?
The solution to expand ln(b^2+(x-a)^2) is ln(b^2+x^2-2ax+a^2)