What is expand Ie^{-t}+B(1-e^{-t})u(t) ?

The solution to expand Ie^{-t}+B(1-e^{-t})u(t) is Ie^{-t}+Btu-Be^{-t}tu

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expand Ie^{-t}+B(1-e^{-t})u(t)

expand

I e^{- t} + B (1 - e^{- t}) u (t)

I e^{- t} + Bt u - B e^{- t} t u

Solution steps

I e^{- t} + B (1 - e^{- t}) u (t)

= e^{- t} I + B (t) u (1 - e^{- t})

Expand

B u (t) (1 - e^{- t}) : Bt u - B e^{- t} t u

= I e^{- t} + Bt u - B e^{- t} t u

\frac{( 1 + 2 i ) ( 1 + 3 i )}{( 3 + 2 i ) ( x + 3 i )}

\frac{e ^{- 2 s} - e ^{- 4 s}}{( s ^{2} + 1 ) s}

\frac{x ( x - 2 )}{x ^{2} - 9}

(- 2, 6) y (3, - 5)

What is expand Ie^{-t}+B(1-e^{-t})u(t) ?
The solution to expand Ie^{-t}+B(1-e^{-t})u(t) is Ie^{-t}+Btu-Be^{-t}tu