What is expand (x^2+7)/(3x(x+1)(x-1)) ?

The solution to expand (x^2+7)/(3x(x+1)(x-1)) is (x^2+7)/(3x^3-3x)

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expand (x^2+7)/(3x(x+1)(x-1))

expand

\frac{x ^{2} + 7}{3 x ( x + 1 ) ( x - 1 )}

\frac{x ^{2} + 7}{3 x ^{3} - 3 x}

Solution steps

\frac{x ^{2} + 7}{3 x ( x + 1 ) ( x - 1 )}

Expand

3 x (x + 1) (x - 1) : 3 x^{3} - 3 x

= \frac{x ^{2} + 7}{3 x ^{3} - 3 x}

\frac{( - 4 a - 3 ) ( a - 1 )}{( a + 3 ) ( 2 a - 29 )}

(1 - cos (θ))^{2} + sin^{2} (θ) d θ

\frac{2 x ^{3} - 5 x ^{2} + 4 x}{( x - 1 ) ^{2}}

\frac{x ^{2} + 2}{( x + 2 ) ^{2} ( x + 3 )}

(\frac{1}{3 - y})^{3}

What is expand (x^2+7)/(3x(x+1)(x-1)) ?
The solution to expand (x^2+7)/(3x(x+1)(x-1)) is (x^2+7)/(3x^3-3x)