What is expand y(1+x^2)y'(x)-x(1+y^2) ?

The solution to expand y(1+x^2)y'(x)-x(1+y^2) is yy'(x)+x^2yy'(x)-x-xy^2

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expand y(1+x^2)y'(x)-x(1+y^2)

expand

y (1 + x^{2}) y^{'} (x) - x (1 + y^{2})

yy' (x) + x^{2} yy' (x) - x - x y^{2}

Solution steps

y (1 + x^{2}) y^{'} (x) - x (1 + y^{2})

Expand

y y^{'} (x) (1 + x^{2}) : y y^{'} (x) + x^{2} y y^{'} (x)

= y y^{'} (x) + x^{2} y y^{'} (x) - x (1 + y^{2})

Expand

- x (1 + y^{2}) : - x - x y^{2}

= y y^{'} (x) + x^{2} y y^{'} (x) - x - x y^{2}

\frac{x}{( x - 1 ) \cdot ( x + 3 )}

\frac{3}{( x ^{2} - 4 ) ( 2 - x )}

((1, 2, 3) + (4, - 3, - 1)) \cdot ((- 5, - 3, 5) - (- 2, 1, 6))

\frac{d}{d y} ((f (y, x)) (3 x + 2 y))

(e^{x} sin (y) + 2 y) d x - (2 x - e^{x} sin (y)) d y

What is expand y(1+x^2)y'(x)-x(1+y^2) ?
The solution to expand y(1+x^2)y'(x)-x(1+y^2) is yy'(x)+x^2yy'(x)-x-xy^2