What is expand-6(-6e^{(-3x^2)}(x^2)+e^{(-3x^2)}) ?

The solution to expand-6(-6e^{(-3x^2)}(x^2)+e^{(-3x^2)}) is 36e^{-3x^2}x^2-6e^{-3x^2}

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expand-6(-6e^{(-3x^2)}(x^2)+e^{(-3x^2)})

expand

- 6 (- 6 e^{(- 3 x^{2})} (x^{2}) + e^{(- 3 x^{2})})

36 e^{- 3 x^{2}} x^{2} - 6 e^{- 3 x^{2}}

Solution steps

- 6 (- 6 e^{(- 3 x^{2})} (x^{2}) + e^{(- 3 x^{2})})

Apply the distributive law:

a (b + c) = ab + a c

a = - 6, b = - 6 e^{(- 3 x^{2})} (x^{2}), c = e^{(- 3 x^{2})}

= - 6 (- 6 e^{(- 3 x^{2})} (x^{2})) + (- 6) e^{(- 3 x^{2})}

Apply minus-plus rules

- (- a) = a, + (- a) = - a

= 6 \cdot 6 e^{(- 3 x^{2})} (x^{2}) - 6 e^{(- 3 x^{2})}

Simplify

6 \cdot 6 e^{(- 3 x^{2})} (x^{2}) - 6 e^{(- 3 x^{2})} : 36 e^{- 3 x^{2}} x^{2} - 6 e^{- 3 x^{2}}

= 36 e^{- 3 x^{2}} x^{2} - 6 e^{- 3 x^{2}}

ln (\frac{x - 4}{( y - 5 ) ( z + 3 ) ^{3}})

\frac{4 ( 10 - 1 )}{3}

320 (\frac{x}{16} + \frac{x}{20} = 1)

\frac{7 x ^{2}}{( x - 4 ) ( x + 7 )}

- 5 (2 + Δ x)

What is expand-6(-6e^{(-3x^2)}(x^2)+e^{(-3x^2)}) ?
The solution to expand-6(-6e^{(-3x^2)}(x^2)+e^{(-3x^2)}) is 36e^{-3x^2}x^2-6e^{-3x^2}