What is expand ((x-4)(x+2))/((x-1)(x-3)) ?

The solution to expand ((x-4)(x+2))/((x-1)(x-3)) is (x^2-2x-8)/(x^2-4x+3)

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expand ((x-4)(x+2))/((x-1)(x-3))

expand

\frac{( x - 4 ) ( x + 2 )}{( x - 1 ) ( x - 3 )}

\frac{x ^{2} - 2 x - 8}{x ^{2} - 4 x + 3}

Solution steps

\frac{( x - 4 ) ( x + 2 )}{( x - 1 ) ( x - 3 )}

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

= \frac{( x - 4 ) ( x + 2 )}{x ^{2} - 4 x + 3}

Expand

(x - 4) (x + 2) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{x ^{2} - 4 x + 3}

sin (2 x) δ (x - 1)

2 (2 + 2 i) \frac{d}{d x} (2 + 2 i)

\frac{k ( k + 2 ) + 1}{( k + 1 ) ( k + 2 )}

\frac{( p - q ) ^{3}}{5}

(e^{x + y} - e^{x}) d x + (e^{x + y} + e^{y}) d y

What is expand ((x-4)(x+2))/((x-1)(x-3)) ?
The solution to expand ((x-4)(x+2))/((x-1)(x-3)) is (x^2-2x-8)/(x^2-4x+3)