What is expand ((p-q)^3)/5 ?

The solution to expand ((p-q)^3)/5 is (p^3)/5-(3p^2q)/5+(3pq^2)/5-(q^3)/5

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expand ((p-q)^3)/5

expand

\frac{( p - q ) ^{3}}{5}

\frac{p ^{3}}{5} - \frac{3 p ^{2} q}{5} + \frac{3 p q ^{2}}{5} - \frac{q ^{3}}{5}

Solution steps

\frac{( p - q ) ^{3}}{5}

(p - q)^{3} = p^{3} - 3 p^{2} q + 3 p q^{2} - q^{3}

= \frac{p ^{3} - 3 p ^{2} q + 3 p q ^{2} - q ^{3}}{5}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{p ^{3} - 3 p ^{2} q + 3 p q ^{2} - q ^{3}}{5} = \frac{p ^{3}}{5} - \frac{3 p ^{2} q}{5} + \frac{3 p q ^{2}}{5} - \frac{q ^{3}}{5}

= \frac{p ^{3}}{5} - \frac{3 p ^{2} q}{5} + \frac{3 p q ^{2}}{5} - \frac{q ^{3}}{5}

(e^{x + y} - e^{x}) d x + (e^{x + y} + e^{y}) d y

\frac{( h + 9 ) ^{2}}{h}

\frac{( 2 m + p ) n ^{2}}{( 2 k ^{2} \cdot m + p ) 2 k ^{3}}

\frac{2 ^{\frac{1}{N}}}{N ( 2 ^{\frac{1}{N}} - 1 )}

(\frac{2 - 14}{5})^{2}

What is expand ((p-q)^3)/5 ?
The solution to expand ((p-q)^3)/5 is (p^3)/5-(3p^2q)/5+(3pq^2)/5-(q^3)/5