What is expand 1/((x-1)(x-3)(7x^2+6x+1)) ?

The solution to expand 1/((x-1)(x-3)(7x^2+6x+1)) is 1/(7x^4-22x^3-2x^2+14x+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((x-1)(x-3)(7x^2+6x+1))

expand

\frac{1}{( x - 1 ) ( x - 3 ) ( 7 x ^{2} + 6 x + 1 )}

\frac{1}{7 x ^{4} - 22 x ^{3} - 2 x ^{2} + 14 x + 3}

Solution steps

\frac{1}{( x - 1 ) ( x - 3 ) ( 7 x ^{2} + 6 x + 1 )}

Expand

(x - 1) (x - 3) (7 x^{2} + 6 x + 1) : 7 x^{4} - 22 x^{3} - 2 x^{2} + 14 x + 3

= \frac{1}{7 x ^{4} - 22 x ^{3} - 2 x ^{2} + 14 x + 3}

cos (x + y) d x + (3 y^{2} + 2 y + cos (x + y)) d y

\frac{s ^{2} ( 2 s ^{2} + 1 )}{( 8 s ^{2} + 9 s + 2 ) ( s ^{3} + 1 )}

\frac{5 x}{3} - 2 (x + 1 = 9)

(2 + \frac{3}{π}) (x - 1)

\frac{( y + 3 ) ( y - 6 )}{( y + 1 ) ( 2 y + 3 )}

What is expand 1/((x-1)(x-3)(7x^2+6x+1)) ?
The solution to expand 1/((x-1)(x-3)(7x^2+6x+1)) is 1/(7x^4-22x^3-2x^2+14x+3)