What is ((x^2-y^2)(y^2-x^2))/(x^2y^2) ?

The solution to ((x^2-y^2)(y^2-x^2))/(x^2y^2) is -((x^2-y^2)^2)/(x^2y^2)

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simplify ((x^2-y^2)(y^2-x^2))/(x^2y^2)

simplify

\frac{( x ^{2} - y ^{2} ) ( y ^{2} - x ^{2} )}{x ^{2} y ^{2}}

- \frac{( x ^{2} - y ^{2} ) ^{2}}{x ^{2} y ^{2}}

Solution steps

\frac{( x ^{2} - y ^{2} ) ( y ^{2} - x ^{2} )}{x ^{2} y ^{2}}

Simplify

(x^{2} - y^{2}) (y^{2} - x^{2}) : - (x^{2} - y^{2})^{2}

= \frac{- ( x ^{2} - y ^{2} ) ^{2}}{x ^{2} y ^{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{( x ^{2} - y ^{2} ) ^{2}}{x ^{2} y ^{2}}

(3 x^{2} + 2 x - 9) (ln (x^{3} - 5 x))

\frac{d}{d t} ((x) (a (t + sin (t) cos (t))))

lo g_{a} (b) lo g_{b} (c) lo g_{c} (a)

1 + \frac{0.024 X}{( s + 0.2 ) ( s + 0.1 )}

a r gu m e n t (1 + i)

What is ((x^2-y^2)(y^2-x^2))/(x^2y^2) ?
The solution to ((x^2-y^2)(y^2-x^2))/(x^2y^2) is -((x^2-y^2)^2)/(x^2y^2)