What is expand 1/((x+3)(x+4)(x+1)) ?

The solution to expand 1/((x+3)(x+4)(x+1)) is 1/(x^3+8x^2+19x+12)

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expand 1/((x+3)(x+4)(x+1))

expand

\frac{1}{( x + 3 ) ( x + 4 ) ( x + 1 )}

\frac{1}{x ^{3} + 8 x ^{2} + 19 x + 12}

Solution steps

\frac{1}{( x + 3 ) ( x + 4 ) ( x + 1 )}

Expand

(x + 3) (x + 4) (x + 1) : x^{3} + 8 x^{2} + 19 x + 12

= \frac{1}{x ^{3} + 8 x ^{2} + 19 x + 12}

(e^{x} sin (2 x)) \cdot (e^{x} cos (2 x) - 2 e^{x} sin (2 x))

(\frac{2}{3} + e) (z - 1)

\frac{3 x}{( 2 - x ) ( a + x ^{2} )}

\frac{( 12 - x - y ) ^{2}}{4}

What is expand 1/((x+3)(x+4)(x+1)) ?
The solution to expand 1/((x+3)(x+4)(x+1)) is 1/(x^3+8x^2+19x+12)