What is expand (70e^{2t}+1/(t+5))dx ?

The solution to expand (70e^{2t}+1/(t+5))dx is 70e^{2t}dx+(dx)/(t+5)

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expand (70e^{2t}+1/(t+5))dx

expand

(70 e^{2 t} + \frac{1}{t + 5}) d x

70 e^{2 t} d x + \frac{d x}{t + 5}

Solution steps

(70 e^{2 t} + \frac{1}{t + 5}) d x

Apply the distributive law:

a (b + c) = ab + a c

a = d x, b = 70 e^{2 t}, c = \frac{1}{t + 5}

= d x \cdot 70 e^{2 t} + d x \frac{1}{t + 5}

= 70 e^{2 t} d x + \frac{1}{t + 5} d x

\frac{1}{t + 5} d x = \frac{d x}{t + 5}

= 70 e^{2 t} d x + \frac{d x}{t + 5}

\frac{x ^{4} + y ^{4} + z ^{4}}{( x ^{2} + y ^{2} + z ^{2} ) ^{2}}

\frac{1}{( x ^{2} + 1 ) x ^{2} + 1}

\frac{( 1 - 3 x ^{2} )}{x ( 1 + 3 x ^{2} )}

\frac{\partial}{\partial t} ((y) (π - t))

59 - 3 (3 x + 5 = 28)

What is expand (70e^{2t}+1/(t+5))dx ?
The solution to expand (70e^{2t}+1/(t+5))dx is 70e^{2t}dx+(dx)/(t+5)