What is expand (7x)/((2x+1)(x-3)) ?

The solution to expand (7x)/((2x+1)(x-3)) is (7x)/(2x^2-5x-3)

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expand (7x)/((2x+1)(x-3))

expand

\frac{7 x}{( 2 x + 1 ) ( x - 3 )}

\frac{7 x}{2 x ^{2} - 5 x - 3}

Solution steps

\frac{7 x}{( 2 x + 1 ) ( x - 3 )}

Expand

(2 x + 1) (x - 3) : 2 x^{2} - 5 x - 3

= \frac{7 x}{2 x ^{2} - 5 x - 3}

\frac{2 ( 3 e ^{3 π} + 1 ) ( 3 e ^{3 π} - 1 )}{e ^{6 π}}

\frac{4 x ^{3}}{( x + 1 ) ^{2} ( x ^{2} - 1 )}

1576 x ((2, \frac{5}{2}) - 1)

\frac{2 ( x - y ) ^{2} ( 3 x + y ) ^{2} ( 1 + x )}{( 1 - x ) ^{4} ( 1 - x + y )}

[(x - 2) e x] \frac{d x}{d x}

What is expand (7x)/((2x+1)(x-3)) ?
The solution to expand (7x)/((2x+1)(x-3)) is (7x)/(2x^2-5x-3)