What is expand ((x^2-3x-4)(x+1))/((x-1)(x^2+2x-3)) ?

The solution to expand ((x^2-3x-4)(x+1))/((x-1)(x^2+2x-3)) is (x^3-2x^2-7x-4)/(x^3+x^2-5x+3)

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expand ((x^2-3x-4)(x+1))/((x-1)(x^2+2x-3))

expand

\frac{( x ^{2} - 3 x - 4 ) ( x + 1 )}{( x - 1 ) ( x ^{2} + 2 x - 3 )}

\frac{x ^{3} - 2 x ^{2} - 7 x - 4}{x ^{3} + x ^{2} - 5 x + 3}

Solution steps

\frac{( x ^{2} - 3 x - 4 ) ( x + 1 )}{( x - 1 ) ( x ^{2} + 2 x - 3 )}

Expand

(x - 1) (x^{2} + 2 x - 3) : x^{3} + x^{2} - 5 x + 3

= \frac{( x ^{2} - 3 x - 4 ) ( x + 1 )}{x ^{3} + x ^{2} - 5 x + 3}

Expand

(x^{2} - 3 x - 4) (x + 1) : x^{3} - 2 x^{2} - 7 x - 4

= \frac{x ^{3} - 2 x ^{2} - 7 x - 4}{x ^{3} + x ^{2} - 5 x + 3}

\frac{( y - 3 ) ^{2}}{4}

(3 - x - 1) (6 - x - 2)

\frac{6 x ^{2} y}{( x ^{2} + x - 20 ) ( x ^{2} + 4 x - 5 )}

\frac{( sin ( x ) + x cos ( x ) ) y}{x sin ( x )}

\frac{( x + 5 ) ( x - 2 )}{2}

What is expand ((x^2-3x-4)(x+1))/((x-1)(x^2+2x-3)) ?
The solution to expand ((x^2-3x-4)(x+1))/((x-1)(x^2+2x-3)) is (x^3-2x^2-7x-4)/(x^3+x^2-5x+3)