What are the solutions to the equation 5x^2+26x-24=0 ?

The solutions to the equation 5x^2+26x-24=0 are x= 4/5 ,x=-6

Find the zeros of 5x^2+26x-24=0

The zeros of 5x^2+26x-24=0 are x= 4/5 ,x=-6

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5 x^{2} + 26 x - 24 = 0

x = \frac{4}{5}, x = - 6

Decimal Notation

x = 0.8, x = - 6

Solution steps

5 x^{2} + 26 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

2 6^{2} - 4 \cdot 5 (- 24) = 34

x_{1, 2} = \frac{- 26 \pm 34}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 26 + 34}{2 \cdot 5}, x_{2} = \frac{- 26 - 34}{2 \cdot 5}

x = \frac{- 26 + 34}{2 \cdot 5} : \frac{4}{5}

x = \frac{- 26 - 34}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - 6

3 y^{3} - 2 y^{2} + 21 y - 14

65 Q - \frac{Q ^{2}}{100} - (722 + \frac{Q ^{2}}{200}) = 0

\frac{1}{5} + \frac{1}{12}

u^{2} - 9 u + 18 = 0

1 0^{\frac{1}{2}} \cdot 1 0^{\frac{1}{2}}

What are the solutions to the equation 5x^2+26x-24=0 ?
The solutions to the equation 5x^2+26x-24=0 are x= 4/5 ,x=-6
Find the zeros of 5x^2+26x-24=0
The zeros of 5x^2+26x-24=0 are x= 4/5 ,x=-6