What is expand ((1000+n^2)^2)/(1000000) ?

The solution to expand ((1000+n^2)^2)/(1000000) is 1+(n^2)/(500)+(n^4)/(1000000)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((1000+n^2)^2)/(1000000)

expand

\frac{( 1000 + n ^{2} ) ^{2}}{1000000}

1 + \frac{n ^{2}}{500} + \frac{n ^{4}}{1000000}

Solution steps

\frac{( 1000 + n ^{2} ) ^{2}}{1000000}

(1000 + n^{2})^{2} = 1000000 + 2000 n^{2} + n^{4}

= \frac{1000000 + 2000 n ^{2} + n ^{4}}{1000000}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1000000 + 2000 n ^{2} + n ^{4}}{1000000} = \frac{1000000}{1000000} + \frac{2000 n ^{2}}{1000000} + \frac{n ^{4}}{1000000}

= \frac{1000000}{1000000} + \frac{2000 n ^{2}}{1000000} + \frac{n ^{4}}{1000000}

Apply rule

\frac{a}{a} = 1

\frac{1000000}{1000000} = 1

= 1 + \frac{2000 n ^{2}}{1000000} + \frac{n ^{4}}{1000000}

Cancel

\frac{2000 n ^{2}}{1000000} : \frac{n ^{2}}{500}

= 1 + \frac{n ^{2}}{500} + \frac{n ^{4}}{1000000}

Z ((n - 1) a^{n - 1})

f (35 (t - \frac{4}{5})) H (t - \frac{4}{5})

- \frac{( h - 8 ) ( h - 12 )}{4}

\frac{1}{( x ^{2} + 1 ) ( s ^{2} + x ^{2} )}

f (t - 6) H (t - 6)

What is expand ((1000+n^2)^2)/(1000000) ?
The solution to expand ((1000+n^2)^2)/(1000000) is 1+(n^2)/(500)+(n^4)/(1000000)