What is expand 1/3 (pi)(h-8)^2h ?

The solution to expand 1/3 (pi)(h-8)^2h is (pih^3)/3-(16pih^2)/3+(64pih)/3

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expand 1/3 (pi)(h-8)^2h

expand

\frac{1}{3} (π) (h - 8)^{2} h

\frac{π h ^{3}}{3} - \frac{16 π h ^{2}}{3} + \frac{64 πh}{3}

Solution steps

\frac{1}{3} (π) (h - 8)^{2} h

Remove parentheses:

(a) = a

= \frac{1}{3} π (h - 8)^{2} h

(h - 8)^{2} = h^{2} - 16 h + 64

= π \frac{1}{3} h (h^{2} - 16 h + 64)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 πh}{3} (h^{2} - 16 h + 64)

Multiply:

1 π = π

= \frac{πh}{3} (h^{2} - 16 h + 64)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{πh ( h ^{2} - 16 h + 64 )}{3}

Expand

πh (h^{2} - 16 h + 64) : π h^{3} - 16 π h^{2} + 64 πh

= \frac{π h ^{3} - 16 π h ^{2} + 64 πh}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π h ^{3} - 16 π h ^{2} + 64 πh}{3} = \frac{π h ^{3}}{3} - \frac{16 π h ^{2}}{3} + \frac{64 πh}{3}

= \frac{π h ^{3}}{3} - \frac{16 π h ^{2}}{3} + \frac{64 πh}{3}

\frac{8000}{( 1 + x ) ^{3}}

\frac{d ^{2}}{d x ^{2}} ((y) (cos (5 x) - 4))

(3 x^{2} + 2 x y - y^{2}) d x + (x^{2} - 2 x y - 3 y^{2}) d y

\frac{507}{s ( s ^{2} - 4 s + 13 ) ^{2}}

\frac{1}{( x ^{2} - A ) ( x ^{2} - B )}

What is expand 1/3 (pi)(h-8)^2h ?
The solution to expand 1/3 (pi)(h-8)^2h is (pih^3)/3-(16pih^2)/3+(64pih)/3