What is expand (16x)/((x^2-1)^2) ?

The solution to expand (16x)/((x^2-1)^2) is (16x)/(x^4-2x^2+1)

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expand (16x)/((x^2-1)^2)

expand

\frac{16 x}{( x ^{2} - 1 ) ^{2}}

\frac{16 x}{x ^{4} - 2 x ^{2} + 1}

Solution steps

\frac{16 x}{( x ^{2} - 1 ) ^{2}}

(x^{2} - 1)^{2} = x^{4} - 2 x^{2} + 1

= \frac{16 x}{x ^{4} - 2 x ^{2} + 1}

\frac{2 3 + 2}{- 3}

\frac{- 2 t ^{5} - 2 t}{( t ^{4} - 1 ) ( t ^{2} - 1 )}

\frac{- b + 1}{( 2 - b ) ( - 2 + b )}

ln (x) (2 x^{2} + x) - x^{2} - x

3 (t + 1 = 18)

What is expand (16x)/((x^2-1)^2) ?
The solution to expand (16x)/((x^2-1)^2) is (16x)/(x^4-2x^2+1)