What is expand (s+1)/((s-2)(s+3)) ?

The solution to expand (s+1)/((s-2)(s+3)) is (s+1)/(s^2+s-6)

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expand (s+1)/((s-2)(s+3))

expand

\frac{s + 1}{( s - 2 ) ( s + 3 )}

\frac{s + 1}{s ^{2} + s - 6}

Solution steps

\frac{s + 1}{( s - 2 ) ( s + 3 )}

Expand

(s - 2) (s + 3) : s^{2} + s - 6

= \frac{s + 1}{s ^{2} + s - 6}

\frac{e ^{t} ( cos ( t ) - cos ( 2 t ) )}{t}

\frac{d}{d x} ((z (x, y)) (x^{3} y - y^{y}))

Z {y (n + 2)}

\frac{3 2 ( x + h ) + 1 - 3 2 x + 1}{h}

(3, 5, - 2) (4 x - 2 y + 3 z - 10 = 0)

What is expand (s+1)/((s-2)(s+3)) ?
The solution to expand (s+1)/((s-2)(s+3)) is (s+1)/(s^2+s-6)