What is expand (f\circ g)(x^2-1)(2x+5) ?

The solution to expand (f\circ g)(x^2-1)(2x+5) is 2\circ fgx^3+5\circ fgx^2-2\circ fgx-5\circ fg

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expand (f\circ g)(x^2-1)(2x+5)

expand

(f \circ g) (x^{2} - 1) (2 x + 5)

2 \circ f g x^{3} + 5 \circ f g x^{2} - 2 \circ f gx - 5 \circ f g

Solution steps

(f \circ g) (x^{2} - 1) (2 x + 5)

= (\circ f g) (x^{2} - 1) (2 x + 5)

Expand

(x^{2} - 1) (2 x + 5) : 2 x^{3} + 5 x^{2} - 2 x - 5

= (f \circ g) (2 x^{3} + 5 x^{2} - 2 x - 5)

Expand

(f \circ g) (2 x^{3} + 5 x^{2} - 2 x - 5) : 2 \circ f g x^{3} + 5 \circ f g x^{2} - 2 \circ f gx - 5 \circ f g

= 2 \circ f g x^{3} + 5 \circ f g x^{2} - 2 \circ f gx - 5 \circ f g

\frac{x}{( x + 1 ) ( x ^{2} + 1 )}

\frac{x + 1}{5 x ( x + 3 )}

\frac{1}{z ( z ^{2} + 1 )}

\frac{e ^{- 4 x}}{( x + 3 ) ( x - 9 )}

(x^{2} - x + 4)^{8}

What is expand (f\circ g)(x^2-1)(2x+5) ?
The solution to expand (f\circ g)(x^2-1)(2x+5) is 2\circ fgx^3+5\circ fgx^2-2\circ fgx-5\circ fg