What is expand ((x-2)(-4x-1))/2 ?

The solution to expand ((x-2)(-4x-1))/2 is -2x^2+(7x)/2+1

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expand ((x-2)(-4x-1))/2

expand

\frac{( x - 2 ) ( - 4 x - 1 )}{2}

- 2 x^{2} + \frac{7 x}{2} + 1

Solution steps

\frac{( x - 2 ) ( - 4 x - 1 )}{2}

Expand

(x - 2) (- 4 x - 1) : - 4 x^{2} + 7 x + 2

= \frac{- 4 x ^{2} + 7 x + 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 4 x ^{2} + 7 x + 2}{2} = - \frac{4 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

= - \frac{4 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= - \frac{4 x ^{2}}{2} + \frac{7 x}{2} + 1

Divide the numbers:

\frac{4}{2} = 2

= - 2 x^{2} + \frac{7 x}{2} + 1

δ (x^{'} - x)

\frac{( A + B ) x + 4 A + 3 B}{( x + 3 ) ( x + 4 )}

\frac{1}{( s + 18 ) ^{2}}

\frac{u ^{2} + v ^{2}}{( u - v ) ( u + v )}

\frac{( x - 2 ) ( x + 3 )}{( x - 1 ) ( x + 2 )}

What is expand ((x-2)(-4x-1))/2 ?
The solution to expand ((x-2)(-4x-1))/2 is -2x^2+(7x)/2+1