What is expand ln(x+2)-((x+2)^3)/3 ?

The solution to expand ln(x+2)-((x+2)^3)/3 is ln(x+2)-(x^3)/3-2x^2-4x-8/3

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expand ln(x+2)-((x+2)^3)/3

expand

ln (x + 2) - \frac{( x + 2 ) ^{3}}{3}

ln (x + 2) - \frac{x ^{3}}{3} - 2 x^{2} - 4 x - \frac{8}{3}

Solution steps

ln (x + 2) - \frac{( x + 2 ) ^{3}}{3}

(x + 2)^{3} = x^{3} + 6 x^{2} + 12 x + 8

= ln (x + 2) - \frac{x ^{3} + 6 x ^{2} + 12 x + 8}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 6 x ^{2} + 12 x + 8}{3} = - (\frac{x ^{3}}{3}) - (\frac{6 x ^{2}}{3}) - (\frac{12 x}{3}) - (\frac{8}{3})

= ln (x + 2) - (\frac{x ^{3}}{3}) - (\frac{6 x ^{2}}{3}) - (\frac{12 x}{3}) - (\frac{8}{3})

Remove parentheses:

(a) = a

= ln (x + 2) - \frac{x ^{3}}{3} - \frac{6 x ^{2}}{3} - \frac{12 x}{3} - \frac{8}{3}

Divide the numbers:

\frac{6}{3} = 2

= ln (x + 2) - \frac{x ^{3}}{3} - 2 x^{2} - \frac{12 x}{3} - \frac{8}{3}

Divide the numbers:

\frac{12}{3} = 4

= ln (x + 2) - \frac{x ^{3}}{3} - 2 x^{2} - 4 x - \frac{8}{3}

sin^{2} (x) (1 - tan^{2} (x) = tan^{2} (x) cos (2 x))

2 π (e^{2} - 2)

\frac{d}{d x} (Q (x, M, C, T)) - (M \cdot C) (x - T)

P (t) 10000 e^{0.2 (t - 1.37)^{2}}

\frac{\partial}{\partial K} ((Q) (3 K^{2} + 3 L))

What is expand ln(x+2)-((x+2)^3)/3 ?
The solution to expand ln(x+2)-((x+2)^3)/3 is ln(x+2)-(x^3)/3-2x^2-4x-8/3