What is (\partial)/(\partial {K)}(({Q})(3{K}^2+3L)) ?

The answer to (\partial)/(\partial {K)}(({Q})(3{K}^2+3L)) is 6{Q}{K}

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(\partial)/(\partial {K)}(({Q})(3{K}^2+3L))

\frac{\partial}{\partial K} ((Q) (3 K^{2} + 3 L))

6 Q K

Solution steps

\frac{\partial}{\partial K} ((Q) (3 K^{2} + 3 L))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= Q \frac{\partial}{\partial K} (3 K^{2} + 3 L)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= Q (\frac{\partial}{\partial K} (3 K^{2}) + \frac{\partial}{\partial K} (3 L))

\frac{\partial}{\partial K} (3 K^{2}) = 6 K

\frac{\partial}{\partial K} (3 L) = 0

= Q (6 K + 0)

Simplify

= 6 Q K

x (e^{x} + 1)

\frac{7 x + 17}{( x - 7 ) ( 3 x + 1 )}

(1 - \frac{x}{5})^{2} d x

\frac{2 ( - 4 s ^{2} + 2 s - 15 )}{( s + 5 ) ( s ^{2} + 2 s + 10 )}

- \frac{19}{( 2 x - 5 ) ^{2}}

What is (\partial)/(\partial {K)}(({Q})(3{K}^2+3L)) ?
The answer to (\partial)/(\partial {K)}(({Q})(3{K}^2+3L)) is 6{Q}{K}