What is expand (1-x/5)^2dx ?

The solution to expand (1-x/5)^2dx is dx-(2xdx)/5+(x^2dx)/(25)

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expand (1-x/5)^2dx

expand

(1 - \frac{x}{5})^{2} d x

d x - \frac{2 x d x}{5} + \frac{x ^{2} d x}{25}

Solution steps

(1 - \frac{x}{5})^{2} d x

(1 - \frac{x}{5})^{2} = 1 - \frac{2 x}{5} + \frac{x ^{2}}{25}

= (\frac{x ^{2}}{25} - \frac{2 x}{5} + 1) d x

Distribute parentheses

= d x \cdot 1 + d x (- \frac{2 x}{5}) + d x \frac{x ^{2}}{25}

Apply minus-plus rules

+ (- a) = - a

= 1 \cdot d x - \frac{2 x}{5} d x + \frac{x ^{2}}{25} d x

Simplify

1 \cdot d x - \frac{2 x}{5} d x + \frac{x ^{2}}{25} d x : d x - \frac{2 x d x}{5} + \frac{x ^{2} d x}{25}

= d x - \frac{2 x d x}{5} + \frac{x ^{2} d x}{25}

\frac{2 ( - 4 s ^{2} + 2 s - 15 )}{( s + 5 ) ( s ^{2} + 2 s + 10 )}

- \frac{19}{( 2 x - 5 ) ^{2}}

\frac{( r + θ ) ( r - θ )}{θ ^{2}}

\frac{( 4 x + 1 ) ( x - 5 )}{x - 4}

\frac{x ^{2} + 7 x + 2}{( x ^{2} - 6 x + 13 ) x}

What is expand (1-x/5)^2dx ?
The solution to expand (1-x/5)^2dx is dx-(2xdx)/5+(x^2dx)/(25)