What is expand ((6-2x)^4)/(108) ?

The solution to expand ((6-2x)^4)/(108) is (4x^4}{27}-\frac{16x^3)/9+8x^2-16x+12

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expand ((6-2x)^4)/(108)

expand

\frac{( 6 - 2 x ) ^{4}}{108}

\frac{4 x ^{4}}{27} - \frac{16 x ^{3}}{9} + 8 x^{2} - 16 x + 12

Solution steps

\frac{( 6 - 2 x ) ^{4}}{108}

(6 - 2 x)^{4} = 1296 - 1728 x + 864 x^{2} - 192 x^{3} + 16 x^{4}

= \frac{1296 - 1728 x + 864 x ^{2} - 192 x ^{3} + 16 x ^{4}}{108}

Factor

1296 - 1728 x + 864 x^{2} - 192 x^{3} + 16 x^{4} : 16 (81 - 108 x + 54 x^{2} - 12 x^{3} + x^{4})

= \frac{16 ( 81 - 108 x + 54 x ^{2} - 12 x ^{3} + x ^{4} )}{108}

Cancel the common factor:

4

= \frac{4 ( x ^{4} - 12 x ^{3} + 54 x ^{2} - 108 x + 81 )}{27}

Expand

4 (x^{4} - 12 x^{3} + 54 x^{2} - 108 x + 81) : 4 x^{4} - 48 x^{3} + 216 x^{2} - 432 x + 324

= \frac{4 x ^{4} - 48 x ^{3} + 216 x ^{2} - 432 x + 324}{27}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{4} - 48 x ^{3} + 216 x ^{2} - 432 x + 324}{27} = \frac{4 x ^{4}}{27} - \frac{48 x ^{3}}{27} + \frac{216 x ^{2}}{27} - \frac{432 x}{27} + \frac{324}{27}

= \frac{4 x ^{4}}{27} - \frac{48 x ^{3}}{27} + \frac{216 x ^{2}}{27} - \frac{432 x}{27} + \frac{324}{27}

\frac{48 x ^{3}}{27} = \frac{16 x ^{3}}{9}

\frac{216 x ^{2}}{27} = 8 x^{2}

\frac{432 x}{27} = 16 x

\frac{324}{27} = 12

= \frac{4 x ^{4}}{27} - \frac{16 x ^{3}}{9} + 8 x^{2} - 16 x + 12

\frac{2 s + 3}{( s - 1 ) ( 2 s + 1 ) ( s + 2 ) ( s + 1 )}

(x - (e^{2} + 1))^{2}

\frac{2 e ^{- 3 s} - 2 e ^{- 4 s}}{s ( s ^{2} + 6 s + 34 )}

e^{y} \cdot (1 + x^{2}) \cdot d y - 2 x (1 + e^{y}) d x

[sin (\frac{( 2 n - 1 ) π}{2})]^{n - 1}

What is expand ((6-2x)^4)/(108) ?
The solution to expand ((6-2x)^4)/(108) is (4x^4}{27}-\frac{16x^3)/9+8x^2-16x+12