What is expand-8(-8e^{-4x^2}x^2+e^{-4x^2}) ?

The solution to expand-8(-8e^{-4x^2}x^2+e^{-4x^2}) is 64e^{-4x^2}x^2-8e^{-4x^2}

Popular >

expand-8(-8e^{-4x^2}x^2+e^{-4x^2})

expand

- 8 (- 8 e^{- 4 x^{2}} x^{2} + e^{- 4 x^{2}})

64 e^{- 4 x^{2}} x^{2} - 8 e^{- 4 x^{2}}

Solution steps

- 8 (- 8 e^{- 4 x^{2}} x^{2} + e^{- 4 x^{2}})

Apply the distributive law:

a (b + c) = ab + a c

a = - 8, b = - 8 e^{- 4 x^{2}} x^{2}, c = e^{- 4 x^{2}}

= - 8 (- 8 e^{- 4 x^{2}} x^{2}) + (- 8) e^{- 4 x^{2}}

Apply minus-plus rules

- (- a) = a, + (- a) = - a

= 8 \cdot 8 e^{- 4 x^{2}} x^{2} - 8 e^{- 4 x^{2}}

Multiply the numbers:

8 \cdot 8 = 64

= 64 e^{- 4 x^{2}} x^{2} - 8 e^{- 4 x^{2}}

sec ((2 n + 1) \cdot 18 0^{\circ})

\frac{1 + x ^{2}}{x ^{2} ( s - 3 ) ^{2}}

\frac{e ^{x} ( 1 - sin ( x ) )}{( 1 - cos ( x ) )}

e^{t^{2}} \cdot (4 t^{3} - 7 t^{2} + 9 t)

\frac{1}{( x - 1 ) ( x ^{2} - x + 1 )}

What is expand-8(-8e^{-4x^2}x^2+e^{-4x^2}) ?
The solution to expand-8(-8e^{-4x^2}x^2+e^{-4x^2}) is 64e^{-4x^2}x^2-8e^{-4x^2}