What is expand ((h-14)(h-16))/8 ?

The solution to expand ((h-14)(h-16))/8 is (h^2)/8-(15h)/4+28

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expand ((h-14)(h-16))/8

expand

\frac{( h - 14 ) ( h - 16 )}{8}

\frac{h ^{2}}{8} - \frac{15 h}{4} + 28

Solution steps

\frac{( h - 14 ) ( h - 16 )}{8}

Expand

(h - 14) (h - 16) : h^{2} - 30 h + 224

= \frac{h ^{2} - 30 h + 224}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{h ^{2} - 30 h + 224}{8} = \frac{h ^{2}}{8} - \frac{30 h}{8} + \frac{224}{8}

= \frac{h ^{2}}{8} - \frac{30 h}{8} + \frac{224}{8}

Cancel

\frac{30 h}{8} : \frac{15 h}{4}

= \frac{h ^{2}}{8} - \frac{15 h}{4} + \frac{224}{8}

Divide the numbers:

\frac{224}{8} = 28

= \frac{h ^{2}}{8} - \frac{15 h}{4} + 28

- \frac{9 + 3 j w}{( 2 j w + 3 ) ( 9 + w ^{2} )}

(A e^{i c} - B e^{i d})^{2}

(- 2) (x - y = 10)

, 4 x^{2} - 1 + (2 x + 1)^{2} + x (2 x + 1)

\frac{1}{2} (e^{\frac{t}{2}} + e^{- \frac{t}{2}})

What is expand ((h-14)(h-16))/8 ?
The solution to expand ((h-14)(h-16))/8 is (h^2)/8-(15h)/4+28