What is expand (4(9^{20}-8^{20}))/(3^{38)} ?

The solution to expand (4(9^{20}-8^{20}))/(3^{38)} is 36-(8^{20}*4)/(3^{38)}

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expand (4(9^{20}-8^{20}))/(3^{38)}

expand

\frac{4 ( 9 ^{20} - 8 ^{20} )}{3 ^{38}}

36 - \frac{8 ^{20} \cdot 4}{3 ^{38}}

Decimal Notation

32.58609 \dots

Solution steps

\frac{4 ( 9 ^{20} - 8 ^{20} )}{3 ^{38}}

Expand

4 (9^{20} - 8^{20}) : 9^{20} \cdot 4 - 8^{20} \cdot 4

= \frac{9 ^{20} \cdot 4 - 8 ^{20} \cdot 4}{3 ^{38}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 ^{20} \cdot 4 - 8 ^{20} \cdot 4}{3 ^{38}} = \frac{9 ^{20} \cdot 4}{3 ^{38}} - \frac{8 ^{20} \cdot 4}{3 ^{38}}

= \frac{9 ^{20} \cdot 4}{3 ^{38}} - \frac{8 ^{20} \cdot 4}{3 ^{38}}

\frac{9 ^{20} \cdot 4}{3 ^{38}} = 36

= 36 - \frac{8 ^{20} \cdot 4}{3 ^{38}}

\frac{( x - 1 ) ^{2}}{( x + 1 )}

x^{2} (e^{3 x^{2}} - e^{x})

\frac{1}{2} (e^{4 t} + e^{- 2 t}) (6 t + 1)

\frac{1}{( 2 s + 1 ) ^{2} ( s - j w )}

(\frac{4 t + 2}{t} + t + 2 t^{3}) (e^{4 t} + t^{3} + 4 e^{2 t})

What is expand (4(9^{20}-8^{20}))/(3^{38)} ?
The solution to expand (4(9^{20}-8^{20}))/(3^{38)} is 36-(8^{20}*4)/(3^{38)}