What is expand 1/(x(x-1)(x-2)(x-3)) ?

The solution to expand 1/(x(x-1)(x-2)(x-3)) is 1/(x^4-6x^3+11x^2-6x)

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expand 1/(x(x-1)(x-2)(x-3))

expand

\frac{1}{x ( x - 1 ) ( x - 2 ) ( x - 3 )}

\frac{1}{x ^{4} - 6 x ^{3} + 11 x ^{2} - 6 x}

Solution steps

\frac{1}{x ( x - 1 ) ( x - 2 ) ( x - 3 )}

Expand

x (x - 1) (x - 2) (x - 3) : x^{4} - 6 x^{3} + 11 x^{2} - 6 x

= \frac{1}{x ^{4} - 6 x ^{3} + 11 x ^{2} - 6 x}

\frac{2 x ^{2} + 2 x - 3}{( 2 x + 1 ) ^{2}}

\frac{56 y - 38}{3 ( y - 3 ) ( 5 y - 2 )}

\frac{s}{( s + 1 ) ( s + 2 )}

\frac{1}{5 ( s - 2 )}

\frac{2 x}{( x ^{2} + 4 ) ^{2}}

What is expand 1/(x(x-1)(x-2)(x-3)) ?
The solution to expand 1/(x(x-1)(x-2)(x-3)) is 1/(x^4-6x^3+11x^2-6x)