What are the solutions to the equation 3x^2-16x+8=0 ?

The solutions to the equation 3x^2-16x+8=0 are x=(2(4+sqrt(10)))/3 ,x=(2(4-sqrt(10)))/3

Find the zeros of 3x^2-16x+8=0

The zeros of 3x^2-16x+8=0 are x=(2(4+sqrt(10)))/3 ,x=(2(4-sqrt(10)))/3

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3 x^{2} - 16 x + 8 = 0

x = \frac{2 ( 4 + 10 )}{3}, x = \frac{2 ( 4 - 10 )}{3}

Solution steps

3 x^{2} - 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 8 = 410

x_{1, 2} = \frac{- ( - 16 ) \pm 4 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 10}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 4 10}{2 \cdot 3}

x = \frac{- ( - 16 ) + 4 10}{2 \cdot 3} : \frac{2 ( 4 + 10 )}{3}

x = \frac{- ( - 16 ) - 4 10}{2 \cdot 3} : \frac{2 ( 4 - 10 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 4 + 10 )}{3}, x = \frac{2 ( 4 - 10 )}{3}

\frac{3 x + 4}{2} = 8

2 x + (2) + 3 = 2

0.4 (2 x + 8) - 0.4 = 0.2 (4 x - 12) + 6 x

(x - 3) (x + 8) = 0

- 8 x + 4 = 36

What are the solutions to the equation 3x^2-16x+8=0 ?
The solutions to the equation 3x^2-16x+8=0 are x=(2(4+sqrt(10)))/3 ,x=(2(4-sqrt(10)))/3
Find the zeros of 3x^2-16x+8=0
The zeros of 3x^2-16x+8=0 are x=(2(4+sqrt(10)))/3 ,x=(2(4-sqrt(10)))/3