What is expand ((x-4)(x+2))/((x+1)(x-6)) ?

The solution to expand ((x-4)(x+2))/((x+1)(x-6)) is (x^2-2x-8)/(x^2-5x-6)

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expand ((x-4)(x+2))/((x+1)(x-6))

expand

\frac{( x - 4 ) ( x + 2 )}{( x + 1 ) ( x - 6 )}

\frac{x ^{2} - 2 x - 8}{x ^{2} - 5 x - 6}

Solution steps

\frac{( x - 4 ) ( x + 2 )}{( x + 1 ) ( x - 6 )}

Expand

(x + 1) (x - 6) : x^{2} - 5 x - 6

= \frac{( x - 4 ) ( x + 2 )}{x ^{2} - 5 x - 6}

Expand

(x - 4) (x + 2) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{x ^{2} - 5 x - 6}

\frac{4}{3} π (\frac{3 a ^{2} b ^{4} - 2 a ^{4} b}{2})^{3}

\frac{x ( 6 x ^{3} + 15 x - 1 )}{3}

\frac{( 90 - 3 x ) ( 5 x + 15 )}{2}

(x + x) d x

lo g_{10} (3) (\frac{x ^{2} y ^{3}}{2 z})

What is expand ((x-4)(x+2))/((x+1)(x-6)) ?
The solution to expand ((x-4)(x+2))/((x+1)(x-6)) is (x^2-2x-8)/(x^2-5x-6)